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4.9x^2-23x+12=0
a = 4.9; b = -23; c = +12;
Δ = b2-4ac
Δ = -232-4·4.9·12
Δ = 293.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-\sqrt{293.8}}{2*4.9}=\frac{23-\sqrt{293.8}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+\sqrt{293.8}}{2*4.9}=\frac{23+\sqrt{293.8}}{9.8} $
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